Answer
$x = 2\sqrt {113}$
Work Step by Step
We can find the third side, $x$, by using the Pythagorean theorem, which states that $a^2 + b^2 = c^2$, where $a$ and $b$ are the legs of the right triangle and $c$ is the hypotenuse.
Let's plug in what we know into the Pythagorean theorem:
$14^2 + 16^2 = x^2$
Evaluate the exponents:
$196 + 256= x^2$
Add to simplify:
$452 = x^2$
Rewrite $452$ as the product of a perfect square and another factor:
$x^2 = 4 • 113$
Take the positive square root to solve for $x$:
$x = 2\sqrt {113}$
