Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 7 - Similarity - 7-4 Similarity in Right Triangles - Practice and Problem-Solving Exercises - Page 467: 52

Answer

$x = 5$ $y = 8$

Work Step by Step

We are given a parallelogram, so we know that the diagonals of a parallelogram bisect one another. Therefore, the segments of a bisected diagonal are equal to one another. $\overline{RT}$ is bisected by $\overline{SV}$, so we can set the two segments of $\overline{RT}$ equal to one another. Conversely, $\overline{VS}$ is bisected by $\overline{VP}$, so we can set the two segments of $\overline{PS}$ equal to one another: $\overline{RP} = \overline{PT}$ $\overline{VP} = \overline{PS}$ Let's plug in the expressions we are given into the two equations: $2x = y + 2$ $y = x + 3$ We can solve for both $x$ and $y$ by setting the two equations up as a system of equations: $2x = y + 2$ $y = x + 3$ Let's get all the variables on one side and the constants on the other: $2x - y = 2$ $-x + y = 3$ We don't have to modify any of the equations because one of the variables in each of the equations differs only in sign. Now, we can add the two equations together: $x = 5$ Now that we have the value for $x$, we can plug in this value for $x$ into one of the original equations to find $y$: $y = x + 3$ Substitute $5$ for $x$: $y = 5 + 3$ Add to solve for $y$: $y = 8$
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