Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 7 - Similarity - 7-4 Similarity in Right Triangles - Practice and Problem-Solving Exercises - Page 466: 38

Answer

$x = 3$

Work Step by Step

We have a right triangle with the altitutde dividing the triangle into two smaller triangles; therefore, these three triangles are all similar to one another. If these triangles are similar, then their corresponding sides are proportional. We are given either values or expressions for the lengths of the shorter leg and hypotenuse of the big triangle and the lengths of the shorter leg and hypotenuse of the smallest triangle. Let's set up a proportion to find the value of $x$: $\frac{x}{x + 3} = \frac{x + 3}{12}$ Cross multiply to get rid of the fractions: $12x = (x + 3)(x + 3)$ Distribute to simplify: $12x = x^2 + 3x + 3x + 9$ Subtract $12x$ from each side of the equation: $0 = x^2 + 3x + 3x - 12x + 9$ Combine like terms: $x^2 - 6x + 9 = 0$ Factor the quadratic equation: $(x - 3)(x - 3) = 0$ Set each factor equal to $0$: $x - 3 = 0$ Add $3$ to each side to solve for $x$: $x = 3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.