Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 7 - Similarity - 7-2 Similar Polygons - Practice and Problem-Solving Exercises - Page 446: 37

Answer

$x = 10$ The scale factor for $\triangle WLJ:\triangle QBV$ is $\frac{2}{1}$.

Work Step by Step

In similar triangles, corresponding sides are proportional. In $\triangle WLJ$ and $\triangle QBV$, we have the following corresponding sides: $WL ≅ QB$ $LJ ≅ BV$ $JW ≅ VQ$ Let's use what we know and put this given information into a proportion: $\frac{WL}{BV} = \frac{JW}{VQ}$ Now we plug in values for the sides: $\frac{x}{5} = \frac{x + 6}{8}$ Cross multiply to get rid of the fraction: $5(x + 6) = 8x$ Distribute on the left side of the equation: $5x + 30 = 8x$ Subtract $5x$ from each side of the equation to move variables to one side of the equation: $3x = 30$ Divide both sides by $3$ to solve for $x$: $x = 10$ To find the scale factor, locate corresponding sides on the two triangles and put them into a ratio: $\frac{WL}{BV} = \frac{x}{5}$ Replace $x$ with $10$: $\frac{WL}{BV} = \frac{10}{5}$ Divide both the numerator and denominator by their greatest common factor, $5$: $\frac{WL}{BV} = \frac{2}{1}$ The scale factor for $\triangle WLJ:\triangle QBV$ is $\frac{2}{1}$.
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