Answer
4 or -3
Work Step by Step
$\frac{x-3}{3}$=$\frac{2}{x+2}$
Cross multiply
3(2)=(x-3)(x+2)
6=$x^{2}$-x-6
0=$x^{2}$-x-12
Factor
(x-4)(x+3)=0
Set each factor to 0 to find solutions for x:
x-4=0
x=4
x+3=0
x=-3
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