Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 6 - Polygons and Quadrilaterals - 6-5 Conditions for Rhombuses, Rectangles, and Squares - Practice and Problem-Solving Exercises - Page 386: 11

Answer

$x = 12$

Work Step by Step

According to theorem 6-17, a rhombus has diagonals that bisect opposite angles. We can set the expressions equal to one another because these two angles are the result of being bisected by the diagonal of this rhombus: $2x + 39 = 6x - 9$ Subtract $6x$ from each side of the equation to move variables to the left side of the equation: $-4x + 39 = -9$ Subtract $39$ from each side of the equation to move constants to the right side of the equation: $-4x = -48$ Divide both sides by $-4$ to solve for $x$: $x = 12$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.