Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 6 - Polygons and Quadrilaterals - 6-4 Properties of Rhombuses, Rectangles, and Squares - Practice and Problem-Solving Exercises - Page 380: 21

Answer

$x = 9$ $LN = 67$ $MP = 67$

Work Step by Step

According to Theorem 6-15, the diagonals of a rectangle are congruent. Therefore, we can set $LN$ and $MP$, the diagonals of $LMNP$, equal to one another to solve for $x$: $LN = MP$ Substitute with the expressions given for each diagonal: $9x - 14 = 7x + 4$ Subtract $7x$ from each side of the equation to move variables to the left side of the equation: $2x - 14 = 4$ Add $14$ to each side of the equation to move constants to the right side of the equation: $2x = 18$ Divide each side by $2$ to solve for $x$: $x = 9$ Now that we have the value of $x$, we can plug $9$ in for $x$ into the expressions for each diagonal to find the length of each diagonal. $LN = 9(9) - 14$ Multiply first, according to order of operations: $LN = 81 - 14$ Subtract to solve: $LN = 67$ Now let's find $MP$: $MP = 7(9) + 4$ Multiply first, according to order of operations: $MP = 63 + 4$ Add to solve: $MP = 67$
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