Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 6 - Polygons and Quadrilaterals - 6-3 Proving That a Quadrilateral Is a Parallelogram - Practice and Problem-Solving Exercises - Page 373: 22

Answer

$x = 15$ $y = 25$

Work Step by Step

In a parallelogram, opposite angles are congruent and consecutive angles are supplementary. $m \angle A + m \angle B = 180$ Let's plug in the knowns: $(3x + 10) + (8x + 5) = 180$ Group like terms: $(3x + 8x) + (10 + 5) = 180$ Combine like terms: $11x + 15 = 180$ Subtract $15$ from each side of the equation to isolate constants on the left side of the equation: $11x = 165$ Divide each side of the equation by $11$ to solve for $x$: $x = 15$ Now that we have the value for $x$, we can plug this value into the other equation. Let's set up that equation first: $m \angle A + m \angle D = 180$ Let's plug in our knowns: $(3x + 10) + 5y = 180$ Substitute $15$ for $x$: $3(15) + 10 + 5y = 180$ Multiply first, according to order of operations: $45 + 10 + 5y = 180$ Add on the left side to simplify: $55 + 5y = 180$ Subtract $55$ from both sides of the equation to isolate constants on the right side of the equation: $5y = 125$ Divide each side by $5$ to solve for $y$: $y = 25$
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