Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 13 - Probability - Chapter Test - Page 875: 11

Answer

15

Work Step by Step

We know that: $x! = x(x-1)(x-2)...(1)$ Thus, we have: $ \frac{6!}{4!} = \frac{6*5*4*3*2*1}{4*3*2*1*2*1}= 15$
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