Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 13 - Probability - 13-3 Permutations and Combinations - Got It? - Page 839: 5

Answer

120

Work Step by Step

This is given by $_{10}C_3$ We know that: $_nC_r =\frac{_nP_r}{r!} = \frac{n!}{(n-r)!r!}$ $_{10}C_3 = \frac{10!}{(10-3)!3!}$ We also know that: $x! = x(x-1)(x-2)...(1)$ Thus, we have: 120
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