Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 10 - Area - 10-8 Geometric Probability - Lesson Check - Page 671: 1

Answer

$\dfrac{3}{7}$

Work Step by Step

The probability that the point $T$ lies in the segment $\overline{AB}$ can be computed as: $P(T \in \overline{AB})=\dfrac{AB}{AD}$ Where, $AB=6-3=3$ and $AD=10-3=7$ Now, $P(T \in \overline{AB})=\dfrac{AB}{AD}=\dfrac{6-3}{10-3}=\dfrac{3}{7}$
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