Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 8 - Section 8.2 - Perimeter and Area of Polygons - Exercises - Page 371: 24a

Answer

$\frac{4}{25}$

Work Step by Step

The ratio of the areas of two similar triangles equals the square of the ratio of the lengths of any two corresponding sides; that is, $\frac{A1}{A2}$ = $(\frac{a1}{a2})^{2}$ It will be applicable to any polygon like square, recangle etc Given that the ratio of the length of the corresponding sides = $\frac{s1}{s2}$ = $\frac{2}{5}$ The ratio of $\frac{A1}{A2}$ = $(\frac{a1}{a2})^{2}$ = $(\frac{2}{5})^{2}$ = $\frac{4}{25}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.