Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 5 - Section 5.3 - Proving Lines Parallel - Exercises - Page 243: 28

Answer

CE=8

Work Step by Step

$\frac{CE}{CA}$=$\frac{CD}{CB}$ $\frac{CE}{16}$=$\frac{10}{CE+12}$ CE$^2$+12CE-160=0 (CE+20)(CE-8)=0 CE=8
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