Answer
BC$\approx$14.5
Work Step by Step
$\frac{AC}{EA}$=$\frac{BC}{DE}$
$\frac{20}{20-BC}$=$\frac{BC}{4}$
20BC-BC$^2$=80
BC$^2$-20BC+80=0
BC=$\frac{20+\sqrt {400-320}}{2}$
BC=10+.5$\sqrt {80}$
BC$\approx$14.5
Elementary Geometry for College Students (5th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Brooks Cole
ISBN 10:
1439047901
ISBN 13:
978-1-43904-790-3
Chapter 5 - Section 5.2 - Similar Polygons - Exercises - Page 234: 23
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