Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 3 - Test - Page 175: 15

Answer

$\overline{EB}$

Work Step by Step

AD$^{2}$+AC$^{2}$=DC$^{2}$ 4$^{2}$+7$^{2}$=DC$^{2}$ 16+49=DC$^{2}$ DC=$\sqrt {65}$$\approx$8.1 AE$^{2}$+AB$^{2}$=EB$^{2}$ 7$^{2}$+5$^{2}$=EB$^{2}$ 49+25=EB$^{2}$ EB=$\sqrt {74}$$\approx$8.6 EB$\gt$DC
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