Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter - Section 11.4 - Applications with Acute Triangles - Exercises - Page 529: 39

Answer

63.7

Work Step by Step

Using the law of cosines, we find: $$ a^2=b^2+c^2-2bc\cdot \cos \left(\alpha \right) \\ a=\sqrt{b^2+c^2-2bc\cos \left(α\right)}\\ a=\sqrt{60.5^2+90^2-2\cdot \:60.5\cdot \:90\cos \left(45^{\circ \:}\right)}\\ a=63.7$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.