Answer
1 in
Work Step by Step
A circle is inscribed in a triangle having sides of length 3in, 4in and 5in
the area of the triangle 6 $in^{2}$
Where P represents the perimeter of a triangle and r represents the length of the radius of its inscribed circle, the area of the triangle is given by
A = $\frac{1}{2}$rP
Perimeter of triangle = 3+4+5 = 12 in.
6 = $\frac{1}{2}$*r*12
6= 6r
r = 1in
Therefore the radius of the inscribed circle = 1 in.
