Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 8 - Section 8.3 - Regular Polygons and Area - Exercises - Page 377: 31

Answer

A) $$ A = \frac{3s^2}{4}\sqrt3$$ B) $$A=3s^2$$

Work Step by Step

(A) According to the book, the area of an equilateral triangle is: $$ A = \frac{s^2}{4}\sqrt3$$ Thus, the area of the shaded area is: $$ A = \frac{(2s)^2}{4}\sqrt3 - \frac{s^2}{4}\sqrt3\\ A = \frac{3s^2}{4}\sqrt3$$ (B) For a square: $$ A= s^2 \\ A = (2s)^2 -s^2 \\ A = 3s^2 $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.