Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 8 - Section 8.1 - Area and Initial Postulates - Exercises - Page 361: 49

Answer

8

Work Step by Step

Lets take MN = b =12 h =QR = 6 Area of Parallelogram = bh = 12 * 6 =72 Now lets take PN = QM =9 =b h= QS A = 9h As we know area of parallelogram is same 72 = 9h h = $\frac{72}{9}$= 8
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