Answer
m$\angle$VPS=168$^{\circ}$
Work Step by Step
The interior angles of a regular pentagon have a measure of 108 degrees.
m$\angle$VQP=108-m$\angle$PQR
m$\angle$VQP=108-60=48
m$\angle$VPQ=.5(180-m$\angle$VQP)
m$\angle$VPQ=.5(132)=66
m$\angle$RPS=m$\angle$VPQ=66
m$\angle$VPS=360-m$\angle$RPS-m$\angle$VPQ-m$\angle$QPR
m$\angle$VPS=360-66-66-60
m$\angle$VPS=168$^{\circ}$
