Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 6 - Section 6.2 - More Angle Measures in the Circle - Exercises - Page 294: 7c

Answer

m$\angle$2=15$^{\circ}$

Work Step by Step

NP=MP-NM NP=112-60=52$^{\circ}$ TV=180-MP-MT TV=180-112-46=22$^{\circ}$ m$\angle$2=.5(NP-TV) m$\angle$2=.5(52-22) m$\angle$2=.5(30)=15$^{\circ}$
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