Answer
$\sqrt{45}$
Work Step by Step
We use the theorems in the chapter to obtain:
$EC CD = AC BC \\ 2ED(CD) = 3(30)$
We know CD and ED are equal, so we find:
$2ED^2 = 90 \\ ED = \sqrt{45}$
Elementary Geometry for College Students (7th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Cengage
ISBN 10:
978-1-337-61408-5
ISBN 13:
978-1-33761-408-5
Chapter 6 - Review Exercises - Page 315: 24g
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