Answer
EF=4$\frac{1}{6}$
FG=3$\frac{1}{3}$
GH=2$\frac{1}{2}$
Work Step by Step
AD=AB+BC+CD
AD=5+4+3
AD=12
$\frac{EF}{EH}$=$\frac{AB}{AD}$
$\frac{EF}{10}$=$\frac{5}{12}$
12EF=50
EF=4$\frac{1}{6}$
$\frac{FG}{EH}$=$\frac{BC}{AD}$
$\frac{FG}{10}$=$\frac{4}{12}$
12FG=40
FG=3$\frac{1}{3}$
(AD)GH=(EH)CD
12GH=30
GH=2$\frac{1}{2}$
