Answer
So $HL= 6$
$HK = 12$
$MK= 6$
Work Step by Step
In $\triangle HKL$
$\angle HKL = 30^{\circ}$
So $ \angle LHK =60^{\circ}$
now By Theorem 5.5.2/ (30-60-90 Theorem)
$LK= 6\sqrt 3 $ given
So $HL= 6$
$HK = 12$
$MK= HK/2 = 12/2= 6$
Elementary Geometry for College Students (7th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Cengage
ISBN 10:
978-1-337-61408-5
ISBN 13:
978-1-33761-408-5
Chapter 5 - Section 5.5 - Special Right Triangles - Exercises - Page 259: 13
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