Answer
$\overline{DE}=6$
Work Step by Step
Let $b=\overline{DE}$
$12^{2}=(6\sqrt 3)^{2}+b^{2}$
$144=108+b^{2}$
Subtract 108 on both sides
$36=b^{2}$
$6=b$
Elementary Geometry for College Students (7th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Cengage
ISBN 10:
978-1-337-61408-5
ISBN 13:
978-1-33761-408-5
Chapter 5 - Section 5.4 - The Pythagorean Theorem - Exercises - Page 252: 8b
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