Answer
BC$\approx$14.5
Work Step by Step
$\frac{AC}{EA}$=$\frac{BC}{DE}$
$\frac{20}{20-BC}$=$\frac{BC}{4}$
20BC-BC$^2$=80
BC$^2$-20BC+80=0
BC=$\frac{20+\sqrt {400-320}}{2}$
BC=10+.5$\sqrt {80}$
BC$\approx$14.5
Elementary Geometry for College Students (7th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Cengage
ISBN 10:
978-1-337-61408-5
ISBN 13:
978-1-33761-408-5
Chapter 5 - Section 5.2 - Similar Polygons - Exercises - Page 236: 23
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