Answer
$x=-\frac{5}{6}$ or $3$
Work Step by Step
$\frac{2x+1}{x+1} = \frac{14}{3x-1}$
$(2x+1)(3x-1) = 14(x+1)$
$6x^{2}+x-1 = 14x + 14$
$6x^{2}-13x-15 = 0$
$(6x+5)(x-3) = 0$
$6x+5=0$
$6x=-5$
$x=-\frac{5}{6}$
or
$x-3=0$
$x=3$
Elementary Geometry for College Students (7th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Cengage
ISBN 10:
978-1-337-61408-5
ISBN 13:
978-1-33761-408-5
Chapter 5 - Section 5.1 - Ratios, Rates, and Proportions - Exercises - Page 228: 11b
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