Answer
BE=$\sqrt {68}$$\approx$8.2
Work Step by Step
DE$^{2}$+AD$^{2}$=AE$^{2}$
DE$^{2}$=10$^{2}$-8$^{2}$
DE=6
CE=CD-DE
CE=8-6
CE=2
BC$^{2}$+CE$^{2}$=BE$^{2}$
8$^{2}$+2$^{2}$=BE$^{2}$
BE=$\sqrt {68}$$\approx$8.2
Elementary Geometry for College Students (7th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Cengage
ISBN 10:
978-1-337-61408-5
ISBN 13:
978-1-33761-408-5
Chapter 4 - Section 4.3 - The Rectangle, Square, and Rhombus - Exercises - Page 206: 44
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