Chapter 11 - Section 11.3 - The Tangent Ratio and Other Ratios - Exercises - Page 520: 39

The distance from the plane to touch down is $\approx 1376.8$ ft.

1. Use the sine law to solve for $x$ $\frac{x}{sin90} = \frac{120}{sin5}$ $x = \frac{120sin90}{sin5}$ $x = \frac{120}{0.087155...}$ $x = 1376.845...$ ft $x \approx 1376.8$ ft