Answer
$a\approx10.9$ ft
$b\approx11.7$ ft
Work Step by Step
$\sin47^{\circ}=\frac{b}{16}$
$b=16\times\sin47^{\circ}$
$b\approx11.7$
Using Pythagorean Theorem to find $a$.
$a=\sqrt {16^{2}-b^{2}}$
$a\approx\sqrt{16^{2}-11.7^{2}}$
$a\approx10.9$
Elementary Geometry for College Students (7th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Cengage
ISBN 10:
978-1-337-61408-5
ISBN 13:
978-1-33761-408-5
Chapter 11 - Section 11.1 - The Sine Ratio and Applications - Exercises - Page 504: 17
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