Answer
$y^2-9 = (y+3)~(y-3)$
Work Step by Step
The general form of factoring the difference of two squares is as follows:
$x^2-y^2 = (x+y)~(x-y)$
We can factor the difference of the two squares:
$y^2-9 = (y+3)~(y-3)$
Elementary Geometry for College Students (7th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Cengage
ISBN 10:
978-1-337-61408-5
ISBN 13:
978-1-33761-408-5
Appendix A - A.4 - Quadratic Equations - Exercises - Page 556: 5
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