Answer
$x \leq -2$
Work Step by Step
$x^{2} + 4x\leq x(x-5)-18$
$x^{2} + 4x \leq x^{2} - 5x - 18$
$x^{2} - x^{2} + 4x + 5x + 18 \leq 0$
$9x + 18 \leq 0$
$9x \leq -18$
$x \leq -2$
Elementary Geometry for College Students (7th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Cengage
ISBN 10:
978-1-337-61408-5
ISBN 13:
978-1-33761-408-5
Appendix A - A.3 - Inequalities - Exercises - Page 551: 27
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