Answer
A=36$\pi$$\approx$113
Work Step by Step
The diameter of the inscribed circle is equal to the height of the isosceles trapezoid.
h$^2$=13$^2$-($\frac{1}{2}$(18-8))$^2$
h$^2$=169-25=144
h=12
r=.5h
r=6
A=$\pi$r$^2$
A=36$\pi$$\approx$113
Elementary Geometry for College Students (6th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Brooks Cole
ISBN 10:
9781285195698
ISBN 13:
978-1-28519-569-8
Chapter 8 - Section 8.5 - More Area Relationships in the Circle - Exercises - Page 379: 27
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