Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 8 - Section 8.3 - Regular Polygons and Area - Exercises - Page 367: 35

Answer

98.4

Work Step by Step

We assume the length of the first diagonal to be about: $2(8.2)=16.4$ The apothem is 12, and this is the other diagonal. Thus, we approximate area: $A = \frac{d_1d_2}{2} = \frac{16.4 \times 12}{2} \approx 98.4$
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