Answer
20 $unit^{2}$
Work Step by Step
The area of any quadrilateral with perpendicular diagonals of length d1 and d2 is given by
A =$\frac{1}{2}$ d1 * d2
d1 = AC= 8
d2 = BD = 5
The area of ABCD = \frac{1}{2}$ *8* 5 = 20 $unit^{2}$
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