Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 8 - Review Exercises - Page 385: 12

Answer

A=168

Work Step by Step

AE$^2$=AB$^2$-BE$^2$ AE$^2$=100-64=36 AE=6 EC$^2$=BC$^2$-BE$^2$ EC$^2$=289-64=225 EC=15 A=(BE)(AE)+(BE)(EC) A=48+120 A=168
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