Answer
$c=\sqrt 41$
Work Step by Step
Using Pythagorean's Theorem...
$a^{2}+b^{2}=c^{2}$
Substitute in known lengths...
$5^{2}+4^{2}=c^{2}$
Simplify...
$25+15=c^{2}$
$41=c^{2}$
Square root both sides...
$\sqrt 41=c$
Elementary Geometry for College Students (6th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Brooks Cole
ISBN 10:
9781285195698
ISBN 13:
978-1-28519-569-8
Chapter 5 - Test - Page 264: 7a
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