Answer
BD=4$\sqrt 3$$\approx$6.93
Work Step by Step
2AC=AB
AC=6
BC=AC$\sqrt 3$
BC=6$\sqrt 3$
DC$\sqrt 3$=AC
DC=2$\sqrt 3$
BD=BC-DC
BD=6$\sqrt 3$-2$\sqrt 3$
BD=4$\sqrt 3$$\approx$6.93
Elementary Geometry for College Students (6th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Brooks Cole
ISBN 10:
9781285195698
ISBN 13:
978-1-28519-569-8
Chapter 5 - Section 5.5 - Special Right Triangles - Exercises - Page 248: 31
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