Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 5 - Section 5.5 - Special Right Triangles - Exercises - Page 247: 16

Answer

PM=10 NP=10

Work Step by Step

PM=NP=$\frac{MN}{\sqrt 2}$ PM=NP=$\frac{10\sqrt 2}{\sqrt 2}$ PM=NP=10
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.