Answer
$AD=13$
Work Step by Step
In $\triangle ABC$
$AC^{2}=AB^{2}+BC^{2}$
$AC^{2}=4^{2}+3^{2}$
so AC = 5
In $\triangle ACD$
$AD^{2}=AC^{2}+DC^{2}$
$AD^{2}=5^{2}+12^{2}$
$AD^{2}=25+144$
$AD^{2}=169$
$AD=13$
Elementary Geometry for College Students (6th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Brooks Cole
ISBN 10:
9781285195698
ISBN 13:
978-1-28519-569-8
Chapter 5 - Section 5.4 - The Pythagorean Theorem - Exercises - Page 241: 32
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