Answer
DC=8$\frac{1}{3}$
Work Step by Step
BD$^2$+AD$^2$=AB$^2$
AB=$\sqrt {34}$
$\frac{DC+BD}{AB}$=$\frac{AB}{BD}$
$\frac{DC+3}{\sqrt {34}}$=$\frac{\sqrt {34}}{3}$
3DC+9=34
3DC=25
DC=8$\frac{1}{3}$
Elementary Geometry for College Students (6th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Brooks Cole
ISBN 10:
9781285195698
ISBN 13:
978-1-28519-569-8
Chapter 5 - Review Exercises - Page 263: 30a
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