Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 4 - Section 4.1 - Properties of a Parallelogram - Exercises - Page 178: 36c

Answer

Equilateral triangle

Work Step by Step

$\angle$BCE=$\frac{1}{2}$$\angle$C $\angle$B+$\angle$C=180 $\angle$B+$\angle$BCE+$\angle$BEC=180 $\angle$B+$\frac{1}{2}$$\angle$C+$\angle$BEC=180 $\angle$B+$\frac{1}{2}$$\angle$C+$\angle$BEC=$\angle$B+$\angle$C $\angle$BEC=$\frac{1}{2}$$\angle$C Since two angles have a measure equal to half of angle C, it must be an equilateral triangle.
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