Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 11 - Section 11.4 - Applications with Acute Triangles - Exercises - Page 519: 6b

Answer

$8^{2}$ = $(6)^{2}$ + $(9)^{2}$ - 2*6*9*cos β

Work Step by Step

Given data a=6,b =8, c=9 Using theorem 11.4.3 In triangle ABC $b^{2}$ = $a^{2}$ + $c^{2}$ - 2ac cos β $8^{2}$ = $(6)^{2}$ + $(9)^{2}$ - 2*6*9*cos β
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.