Answer
11.5 in
Work Step by Step
The length of segment BC is:
$ sin( 90 - \beta) = \frac{CB}{AB}$
$AB sin( 90 - \beta) = CB$
$CB=sin(90-55)(20 in)=11.5 in$
Elementary Geometry for College Students (6th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Brooks Cole
ISBN 10:
9781285195698
ISBN 13:
978-1-28519-569-8
Chapter 11 - Section 11.1 - The Sine Ratio and Applications - Exercises - Page 497: 36a
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