Answer
$y = -(b/a)x+ \frac{(gb+ah)}{a}$
Work Step by Step
If the line is perpendicular to the line with slope a/b, then it must have slope -b/a. Using point slope form, we see:
$y-h = -b/a(x-g)$
$y = -(b/a)x+(gb/a)+h$
Thus, the slope intercept form is:
$y = -(b/a)x+ \frac{(gb+ah)}{a}$
