Answer
$a = 15$
$b = -2$
$c=-56$
Work Step by Step
A quadratic equation can be written in this form:
$ax^2 + bx+c = 0$
where $a,b,$ and $c$ are real numbers and $a \neq 0$
We can use the quadratic formula to find the solutions of the equation:
$x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$
We can determine the values of $a, b,$ and $c$:
$(3x+2)(5x-4) = 48$
$15x^2-2x-8 = 48$
$15x^2-2x-56 = 0$
$a = 15$
$b = -2$
$c=-56$
