Answer
$8 m^2$
Work Step by Step
The area, A, can be found as:
$A=2^2+(\sqrt 2)^2+(1)^2+(\dfrac{1}{\sqrt 2})^2+....=4+2+1+\dfrac{1}{2}$
or, $A=\dfrac{4}{1-\dfrac{1}{2}}=8 m^2$
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