University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 12 - Section 12.1 - Curves in Space and Their Tangents - Exercises - Page 650: 34

Answer

$u'=\lt 0,0,0 \gt =0$

Work Step by Step

Consider, $c(t)=\lt c_1, c_2, c_3 \gt$ Here, $c_1, c_2, c_3$ are taken as constants Since, $u=c \implies \dfrac{d}{dt}u=\dfrac{d}{dt}c$ or, $u'=\lt \dfrac{d}{dt}c_1, \dfrac{d}{dt}c_2, \dfrac{d}{dt}c_3 \gt$ Thus $u'=\lt 0,0,0 \gt =0$
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