Chapter 11 - Section 11.5 - Lines and Planes in Space - Exercises - Page 630: 11

$x=t,y=0, z=0$

The parametric equations of a straight line can be found by knowing the value of a vector, such as $v=v_1i+v_2j+v_3k$, passing through a point $P(x_0,y_0,z_0)$ as follows: $x=x_0+t v_1,y=y_0+t v_2; z=z_0+t v_3$ Here, we have the vector $v=\lt 1,0,0 \gt$ and $P=(0,0,0)$ . Thus, we get the parametric equations: $x=0+1t,y=0+0t, z=0+0t$ Hence, $x=t,y=0, z=0$