University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 10 - Section 10.1 - Parametrizations of Plane Curves - Exercises - Page 562: 15

Answer

$x=y^{2}$ .

Work Step by Step

Pythagorean trigonometric identity: $\sec^{2}t=\tan^{2}t+1$ leads to $\sec^{2}t-1=(\tan t)^{2}$ $x=y^{2}$ To graph, create a function value table using values for t, in ascending order of t, calculating the x- and y-coordinates of points on the graph. Plot and join the points obtained with a smooth curve, noting the direction in which t increases.
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